1.[PdCl4]2−[\text{PdCl}_4]^{2-}[PdCl4]2− is:a.Tetrahedral, 2 unpaired e−e^-e−b.Square planar, paramagneticc.Square planar, diamagneticd.Tetrahedral, diamagneticLogin to continueOnly logged in users canattempt or see the solution.
