1.limx→08sin8x{1−cos(x2/2)−cos(x2/4)+cos(x2/2)cos(x2/4)}\displaystyle\lim_{x\to0}\frac{8}{\sin^8x}\{1-\cos(x^2/2)-\cos(x^2/4)+\cos(x^2/2)\cos(x^2/4)\}x→0limsin8x8{1−cos(x2/2)−cos(x2/4)+cos(x2/2)cos(x2/4)}a.1/161/161/16b.1/321/321/32c.1/641/641/64d.1/81/81/8Login to continueOnly logged in users canattempt or see the solution.