1.If A=∣x−22x−33x−42x−33x−44x−53x−55x−810x−17∣=Ax3+Bx2+Cx+DA = \begin{vmatrix} x-2 & 2x-3 & 3x-4 \\ 2x-3 & 3x-4 & 4x-5 \\ 3x-5 & 5x-8 & 10x-17 \end{vmatrix} = Ax^3 + Bx^2 + Cx + DA=x−22x−33x−52x−33x−45x−83x−44x−510x−17=Ax3+Bx2+Cx+D,then B+CB + CB+C is equal to:a.555b.000c.−3-3−3d.333Login to continueOnly logged in users canattempt or see the solution.
