1.If a⃗,b⃗,c⃗\vec{a}, \vec{b}, \vec{c}a,b,c are three vectors such that a⃗=b⃗+c⃗\vec{a} = \vec{b} + \vec{c}a=b+c and the angle between b⃗\vec{b}b and c⃗\vec{c}c is π2\frac{\pi}{2}2π, thena.∣a⃗∣2=∣b⃗∣2+∣c⃗∣2|\vec{a}|^2 = |\vec{b}|^2 + |\vec{c}|^2∣a∣2=∣b∣2+∣c∣2b.∣b⃗∣2=∣c⃗∣2+∣a⃗∣2|\vec{b}|^2 = |\vec{c}|^2 + |\vec{a}|^2∣b∣2=∣c∣2+∣a∣2c.∣c⃗∣2=∣a⃗∣2+∣b⃗∣2|\vec{c}|^2 = |\vec{a}|^2 + |\vec{b}|^2∣c∣2=∣a∣2+∣b∣2d.2∣a⃗∣2−∣b⃗∣2=∣c⃗∣22|\vec{a}|^2 - |\vec{b}|^2 = |\vec{c}|^22∣a∣2−∣b∣2=∣c∣2Login to continueOnly logged in users canattempt or see the solution.
