1.If z=x+iyz = x + iyz=x+iy satisfies ∣z∣−2=0|z| - 2 = 0∣z∣−2=0 and z−izˉ+5i=0z - i\bar{z} + 5i = 0z−izˉ+5i=0, then:a.x+2y−4=0x + 2y - 4 = 0x+2y−4=0b.x2+y−4=0x^2 + y - 4 = 0x2+y−4=0c.x+2y+4=0x + 2y + 4 = 0x+2y+4=0d.x2y+3=0x^2 y + 3 = 0x2y+3=0Login to continueOnly logged in users canattempt or see the solution.
