1.Let α\alphaα and β\betaβ be the roots of equation x2−6x−2=0x^2 - 6x - 2 = 0x2−6x−2=0. If an=αn−βna_n = \alpha^n - \beta^nan=αn−βn, ∀n≥1\forall n \ge 1∀n≥1, then the value of a10−2a82a9\frac{a_{10} - 2a_8}{2a_9}2a9a10−2a8 is equal toa.−3-3−3b.666c.−6-6−6d.333Login to continueOnly logged in users canattempt or see the solution.
