1.A capacitor of capacitance CCC, is connected across an AC source of voltage VVV, given by V=V0sin(ωt)V = V_0 \sin(\omega t)V=V0sin(ωt). The displacement current between the plates of the capacitor would then be given bya.Id=V0ωCsin(ωt)I_d = \frac{V_0}{\omega C} \sin(\omega t)Id=ωCV0sin(ωt)b.Id=V0ωCcos(ωt)I_d = \frac{V_0}{\omega C} \cos(\omega t)Id=ωCV0cos(ωt)c.Id=V0ωCcos(ωt)I_d = V_0 \omega C \cos(\omega t)Id=V0ωCcos(ωt)d.Id=V0ωCsin(ωt)I_d = V_0 \omega C \sin(\omega t)Id=V0ωCsin(ωt)Login to continueOnly logged in users canattempt or see the solution.