1.The solution of the differential equation (x+1)dydx−y=e3x(x+1)2(x + 1)\frac{dy}{dx} - y = e^{3x}(x + 1)^2(x+1)dxdy−y=e3x(x+1)2 isa.y=(x+1)e3x+cy = (x + 1)e^{3x} + cy=(x+1)e3x+cb.3y=(x+1)+e3x+c3y = (x + 1) + e^{3x} + c3y=(x+1)+e3x+cc.3yx+1=e3x+c\frac{3y}{x+1} = e^{3x} + cx+13y=e3x+cd.ye−3x=3(x+1)+cye^{-3x} = 3(x + 1) + cye−3x=3(x+1)+cLogin to continueOnly logged in users canattempt or see the solution.