1.Let A=[3−t10−13−t10−13−t]A = \begin{bmatrix} 3-t & 1 & 0 \\ -1 & 3-t & 1 \\ 0 & -1 & 3-t \end{bmatrix}A=3−t−1013−t−1013−t and detA=5\det A = 5detA=5. Then find ttt.a.t=1t = 1t=1b.t=2t = 2t=2c.t=−1t = -1t=−1d.t=−2t = -2t=−2Login to continueOnly logged in users canattempt or see the solution.
