1.Let A=(mnpq)A = \begin{pmatrix} m & n \\ p & q \end{pmatrix}A=(mpnq), d=∣A∣≠0d = |A| \neq 0d=∣A∣=0 and ∣A−d(adj A)∣=0|A - d(\text{adj}\, A)| = 0∣A−d(adjA)∣=0. Then:a.(1+d)2=(m+q)2(1 + d)^2 = (m + q)^2(1+d)2=(m+q)2b.1+d2=(m+q)21 + d^2 = (m + q)^21+d2=(m+q)2c.(1+d)2=m2+q2(1 + d)^2 = m^2 + q^2(1+d)2=m2+q2d.1+d2=m2+q21 + d^2 = m^2 + q^21+d2=m2+q2Login to continueOnly logged in users canattempt or see the solution.
