1.The statement among the following that is a tautology is:a.A∨(∼A∧B)A \vee (\sim A \wedge B)A∨(∼A∧B)b.A∧(A∨B)A \wedge (A \vee B)A∧(A∨B)c.B⇒[A∧(A⇒B)]B \Rightarrow [A \wedge (A \Rightarrow B)]B⇒[A∧(A⇒B)]d.[A∧(A⇒B)]⇒B[A \wedge (A \Rightarrow B)] \Rightarrow B[A∧(A⇒B)]⇒BLogin to continueOnly logged in users canattempt or see the solution.
