1.Let [x][x][x] denote greatest integer less than or equal to xxx. If for n∈Nn \in \mathbb{N}n∈N, (1−x+x3)n=∑j=03najxj(1 - x + x^3)^n = \sum_{j=0}^{3n} a_j x^j(1−x+x3)n=∑j=03najxj, then ∑j=0[3n/2]a2j+4∑j=0[(3n−1)/2]a2j+1\sum_{j=0}^{[3n/2]} a_{2j} + 4 \sum_{j=0}^{[(3n-1)/2]} a_{2j+1}∑j=0[3n/2]a2j+4∑j=0[(3n−1)/2]a2j+1 is equal toa.2b.2n−12^{n-1}2n−1c.1d.nnnLogin to continueOnly logged in users canattempt or see the solution.
