1.The area enclosed (in square units) by the curve y=x4−x2y = x^4 - x^2y=x4−x2, the xxx-axis and the vertical lines passing through the two minimum points of the curve isa.482\frac{48}{\sqrt{2}}248b.5482\frac{5}{48\sqrt{2}}4825c.7602\frac{7}{60\sqrt{2}}6027d.7302\frac{7}{30\sqrt{2}}3027Login to continueOnly logged in users canattempt or see the solution.
