1.If (a⃗×b⃗)2+(a⃗⋅b⃗)2=676(\vec{a} \times \vec{b})^2 + (\vec{a} \cdot \vec{b})^2 = 676(a×b)2+(a⋅b)2=676 and ∣b⃗∣=2|\vec{b}| = 2∣b∣=2, then ∣a⃗∣|\vec{a}|∣a∣ is equal toa.131313b.262626c.393939d.None of theseLogin to continueOnly logged in users canattempt or see the solution.
