1.The equation of the director circle of the hyperbola x2/16−y2/4=1x^2/16 - y^2/4 = 1x2/16−y2/4=1 isa.x2+y2=16x^2 + y^2 = 16x2+y2=16b.x2+y2=4x^2 + y^2 = 4x2+y2=4c.x2+y2=20x^2 + y^2 = 20x2+y2=20d.x2+y2=12x^2 + y^2 = 12x2+y2=12Login to continueOnly logged in users canattempt or see the solution.