1.If ∫3x+1(x−3)(x−5)dx=∫Ax−3dx+∫Bx−5dx\int \frac{3x+1}{(x-3)(x-5)}dx = \int \frac{A}{x-3}dx + \int \frac{B}{x-5}dx∫(x−3)(x−5)3x+1dx=∫x−3Adx+∫x−5Bdx, find BBBa.3b.4c.6d.8Login to continueOnly logged in users canattempt or see the solution.
