1.If α,β∈C\alpha, \beta \in \mathbb{C}α,β∈C are the distinct roots of the equation x2−x+1=0x^2 - x + 1 = 0x2−x+1=0, then α101+β107\alpha^{101} + \beta^{107}α101+β107 is equal toa.222b.−1-1−1c.000d.111Login to continueOnly logged in users canattempt or see the solution.
