1.In the nuclear reaction 714N+X→614C+11H^{14}_{7}\text{N} + X \to ^{14}_{6}\text{C} + ^{1}_{1}\text{H}714N+X→614C+11H, the XXX will bea.−10e^{0}_{-1}\text{e}−10eb.11H^{1}_{1}\text{H}11Hc.12H^{2}_{1}\text{H}12Hd.01n^{1}_{0}\text{n}01nLogin to continueOnly logged in users canattempt or see the solution.
