1.tan−1(14)+tan−1(29)\tan^{-1} \left(\frac{1}{4}\right) + \tan^{-1} \left(\frac{2}{9}\right)tan−1(41)+tan−1(92) is equal toa.12cos−1(35)\frac{1}{2} \cos^{-1} \left(\frac{3}{5}\right)21cos−1(53)b.12sin−1(35)\frac{1}{2} \sin^{-1} \left(\frac{3}{5}\right)21sin−1(53)c.12tan−1(35)\frac{1}{2} \tan^{-1} \left(\frac{3}{5}\right)21tan−1(53)d.tan−1(12)\tan^{-1} \left(\frac{1}{2}\right)tan−1(21)Login to continueOnly logged in users canattempt or see the solution.
