1.The differential equation dydx+1xsin2y=x3cos2y\frac{dy}{dx} + \frac{1}{x}\sin 2y = x^3\cos^2 ydxdy+x1sin2y=x3cos2y represents a family of curves given by the equationa.x6+6x2=Ctanyx^6 + 6x^2 = C\tan yx6+6x2=Ctanyb.6x2tany=x6+C6x^2\tan y = x^6 + C6x2tany=x6+Cc.sin2y=x3cos2y+C\sin 2y = x^3\cos^2 y + Csin2y=x3cos2y+Cd.none of theseLogin to continueOnly logged in users canattempt or see the solution.