1.Let v(t)\mathbf{v}(t)v(t) be the velocity of a particle at time ttt. ThenNote: More than one option may be correct.a.∣dvdt∣\left|\dfrac{d\mathbf{v}}{dt}\right|dtdv and d∣v∣dt\dfrac{d|\mathbf{v}|}{dt}dtd∣v∣ are always equalb.∣dvdt∣\left|\dfrac{d\mathbf{v}}{dt}\right|dtdv and d∣v∣dt\dfrac{d|\mathbf{v}|}{dt}dtd∣v∣ may be equalc.d∣v∣dt\dfrac{d|\mathbf{v}|}{dt}dtd∣v∣ can be zero while ∣dvdt∣\left|\dfrac{d\mathbf{v}}{dt}\right|dtdv is not zerod.d∣v∣dt≠0\dfrac{d|\mathbf{v}|}{dt} \neq 0dtd∣v∣=0 implies ∣dvdt∣≠0\left|\dfrac{d\mathbf{v}}{dt}\right| \neq 0dtdv=0Login to continueOnly logged in users canattempt or see the solution.
