1.The standard deviations of xi(i=1,2,…,10)x_i (i=1,2,\ldots,10)xi(i=1,2,…,10) and yi(i=1,…,10)y_i (i=1,\ldots,10)yi(i=1,…,10) are respectively aaa and bbb. xˉ\bar{x}xˉ, yˉ\bar{y}yˉ are the means. If zi=(xi−xˉ)(yi−yˉ)z_i = (x_i-\bar{x})(y_i-\bar{y})zi=(xi−xˉ)(yi−yˉ) and ∑i=110zi=c\sum_{i=1}^{10} z_i = c∑i=110zi=c, then the standard deviation of (xi−yi),(i=1,2,…,10)(x_i-y_i), (i=1,2,\ldots,10)(xi−yi),(i=1,2,…,10) isa.a2+b2+c5\sqrt{a^2 + b^2 + \frac{c}{5}}a2+b2+5cb.a2+b2−c5\sqrt{a^2 + b^2 - \frac{c}{5}}a2+b2−5cc.a2+b2−c25\sqrt{a^2 + b^2 - \frac{c^2}{5}}a2+b2−5c2d.a2+b2+c25\sqrt{a^2 + b^2 + \frac{c^2}{5}}a2+b2+5c2Login to continueOnly logged in users canattempt or see the solution.