1.Let f(x)=ax (a>0)f(x)=a^x\ (a>0)f(x)=ax (a>0) be written as f(x)=f1(x)+f2(x)f(x)=f_1(x)+f_2(x)f(x)=f1(x)+f2(x), where f1(x)f_1(x)f1(x) is an even function and f2(x)f_2(x)f2(x) is an odd function. Then f1(x+y)+f1(x−y)f_1(x+y)+f_1(x-y)f1(x+y)+f1(x−y) equals:Login to continueOnly logged in users canattempt or see the solution.