1.If the roots of the equation x2−5x+16=0x^2 - 5x + 16 = 0x2−5x+16=0 are α,β\alpha, \betaα,β and the roots of the equation x2+px+q=0x^2 + px + q = 0x2+px+q=0 are (α2+β2)(\alpha^2 + \beta^2)(α2+β2) and αβ2\frac{\alpha\beta}{2}2αβ, then -a.p=1p = 1p=1 and q=56q = 56q=56b.p=1p = 1p=1 and q=−56q = -56q=−56c.p=−1p = -1p=−1 and q=56q = 56q=56d.p=−1p = -1p=−1 and q=−56q = -56q=−56Login to continueOnly logged in users canattempt or see the solution.
