1.A vector A⃗\vec{A}A is rotated by a small angle Δθ\Delta\thetaΔθ radians (Δθ≪1\Delta\theta \ll 1Δθ≪1) to get a new vector B⃗\vec{B}B. In that case B⃗−A⃗\vec{B} - \vec{A}B−A is:a.A⃗[1−(Δθ)22]\vec{A}\left[1 - \frac{(\Delta\theta)^2}{2}\right]A[1−2(Δθ)2]b.0c.A⃗Δθ\vec{A} \Delta\thetaAΔθd.B⃗Δθ−A⃗\vec{B} \Delta\theta - \vec{A}BΔθ−ALogin to continueOnly logged in users canattempt or see the solution.
