1.If sum of the first 212121 terms of the series log91/2x+log91/3x+log91/4x+…\log_{9^{1/2}} x + \log_{9^{1/3}} x + \log_{9^{1/4}} x + \dotslog91/2x+log91/3x+log91/4x+… where x>0x > 0x>0 is 504504504, then xxx is equal to:a.243243243b.999c.777d.818181Login to continueOnly logged in users canattempt or see the solution.