1.If α2=5α−3\alpha^2 = 5\alpha - 3α2=5α−3, β2=5β−3\beta^2 = 5\beta - 3β2=5β−3, (α≠β)(\alpha \neq \beta)(α=β), then the value of αβ+βα\frac{\alpha}{\beta} + \frac{\beta}{\alpha}βα+αβ is -a.193\frac{19}{3}319b.253\frac{25}{3}325c.−193-\frac{19}{3}−319d.None of theseLogin to continueOnly logged in users canattempt or see the solution.
