1.The equation of the line passing through the point of intersection of the lines x−3y+2=0x - 3y + 2 = 0x−3y+2=0 and 2x+5y−7=02x + 5y - 7 = 02x+5y−7=0 and perpendicular to the line 3x+2y+5=03x + 2y + 5 = 03x+2y+5=0 isa.2x−3y+1=02x - 3y + 1 = 02x−3y+1=0b.6x−9y+11=06x - 9y + 11 = 06x−9y+11=0c.2x−3y+5=02x - 3y + 5 = 02x−3y+5=0d.3x−2y+1=03x - 2y + 1 = 03x−2y+1=0Login to continueOnly logged in users canattempt or see the solution.
