1.The number of real solutions of the equation 3(x2+1x2)−2(x+1x)+5=03(x^2 + \dfrac{1}{x^2}) - 2(x + \dfrac{1}{x}) + 5 = 03(x2+x21)−2(x+x1)+5=0 is:a.444b.000c.333d.222Login to continueOnly logged in users canattempt or see the solution.
