1.Let the system of linear equationsx+y+kz=2x + y + kz = 2x+y+kz=22x+3y−z=12x + 3y - z = 12x+3y−z=13x+4y+2z=k3x + 4y + 2z = k3x+4y+2z=khave infinitely many solutions. Then the system(k+1)x+(2k−1)y=7(k+1)x + (2k-1)y = 7(k+1)x+(2k−1)y=7(2k+1)x+(k+5)y=10(2k+1)x + (k+5)y = 10(2k+1)x+(k+5)y=10has:a.infinitely many solutionsb.unique solution satisfying x−y=1x - y = 1x−y=1c.no solutiond.unique solution satisfying x+y=1x + y = 1x+y=1Login to continueOnly logged in users canattempt or see the solution.