1.Among the statements:(S1):((p∨q)⇒r)⇔(p⇒r)(S_1): ((p \lor q) \Rightarrow r) \Leftrightarrow (p \Rightarrow r)(S1):((p∨q)⇒r)⇔(p⇒r)(S2):((p∨q)⇒r)⇔((p⇒r)∨(q⇒r))(S_2): ((p \lor q) \Rightarrow r) \Leftrightarrow ((p \Rightarrow r) \lor (q \Rightarrow r))(S2):((p∨q)⇒r)⇔((p⇒r)∨(q⇒r))a.Only (S1)(S_1)(S1) is a tautologyb.Neither (S1)(S_1)(S1) nor (S2)(S_2)(S2) is a tautologyc.Only (S2)(S_2)(S2) is a tautologyd.Both (S1)(S_1)(S1) and (S2)(S_2)(S2) are tautologiesLogin to continueOnly logged in users canattempt or see the solution.
