1.If ∫f(x) dx=F(x)+C\int f(x)\,dx = F(x)+C∫f(x)dx=F(x)+C, then ddt∫g(t)h(t)f(x) dx=\frac{d}{dt}\int_{g(t)}^{h(t)} f(x)\,dx =dtd∫g(t)h(t)f(x)dx=a.f(h(t))−f(g(t))f(h(t))-f(g(t))f(h(t))−f(g(t))b.F(h(t))−F(g(t))F(h(t))-F(g(t))F(h(t))−F(g(t))c.F(h(t))h′(t)−F(g(t))g′(t)F(h(t))h'(t)-F(g(t))g'(t)F(h(t))h′(t)−F(g(t))g′(t)d.f(h(t))h′(t)−f(g(t))g′(t)f(h(t))h'(t)-f(g(t))g'(t)f(h(t))h′(t)−f(g(t))g′(t)Login to continueOnly logged in users canattempt or see the solution.
