1.The locus of the center of the circles such that the point (2,3)(2, 3)(2,3) is the mid point of the chord 5x+2y=165x + 2y = 165x+2y=16 isa.2x−5y+11=02x - 5y + 11 = 02x−5y+11=0b.2x+5y−11=02x + 5y - 11 = 02x+5y−11=0c.2x+5y+11=02x + 5y + 11 = 02x+5y+11=0d.noneLogin to continueOnly logged in users canattempt or see the solution.