1.Let f:R→Rf : \mathbb{R} \to \mathbb{R}f:R→R be differentiable at c∈Rc \in \mathbb{R}c∈R and f(c)=0f(c) = 0f(c)=0. If g(x)=∣f(x)∣g(x) = |f(x)|g(x)=∣f(x)∣, then at x=cx = cx=c, ggg is:Login to continueOnly logged in users canattempt or see the solution.
