1.Let α,β\alpha, \betaα,β be the roots of the equation x2+22x−1=0x^2 + 2\sqrt{2} x - 1 = 0x2+22x−1=0. The quadratic equation, whose roots are α2+3β\alpha^2 + 3\betaα2+3β and α+3β\alpha + 3\betaα+3β, is:a.x2−192x+94−662=0x^2 - 19\sqrt{2} x + 94 - 66\sqrt{2} = 0x2−192x+94−662=0b.x2−182x+95−06=0x^2 - 18\sqrt{2} x + 95 - 06 = 0x2−182x+95−06=0c.x2−195x+95−06=0x^2 - 19\sqrt{5} x + 95 - 06 = 0x2−195x+95−06=0d.x2−195x+94−662=0x^2 - 19\sqrt{5} x + 94 - 66\sqrt{2} = 0x2−195x+94−662=0Login to continueOnly logged in users canattempt or see the solution.
