1.KaK_aKa for HCN is 5×10−105 \times 10^{-10}5×10−10 at 25∘25^\circ25∘C. For maintaining a constant pH = 9, the volume of 5 M KCN solution required to be added to 10 mL of 2 M HCN solution isa.4 mLb.2.5 mLc.2 mLd.6.4 mLLogin to continueOnly logged in users canattempt or see the solution.
