1.Let a⃗\vec{a}a and b⃗\vec{b}b be two non-collinear unit vectors. If u⃗=a⃗−(a⃗⋅b⃗)b⃗\vec{u} = \vec{a} - (\vec{a} \cdot \vec{b})\vec{b}u=a−(a⋅b)b and v⃗=a⃗×b⃗\vec{v} = \vec{a} \times \vec{b}v=a×b, then ∣v⃗∣|\vec{v}|∣v∣ is equal toa.∣u⃗∣|\vec{u}|∣u∣b.∣u⃗+v⃗⋅a⃗∣|\vec{u} + \vec{v}\cdot\vec{a}|∣u+v⋅a∣c.2∣v⃗∣2|\vec{v}|2∣v∣d.∣v⃗+u⃗∣|\vec{v} + \vec{u}|∣v+u∣Login to continueOnly logged in users canattempt or see the solution.
