1.If the system of linear equations7x+11y+αz=135x+4y+7z=β175x+194y+57z=361\begin{aligned} 7x + 11y + \alpha z &= 13 \\ 5x + 4y + 7z &= \beta \\ 175x + 194y + 57z &= 361 \end{aligned}7x+11y+αz5x+4y+7z175x+194y+57z=13=β=361has infinitely many solutions, then α+β+2\alpha + \beta + 2α+β+2 is equal to:a.444b.333c.555d.666Login to continueOnly logged in users canattempt or see the solution.
