1.Let α∈(0,∞)\alpha \in (0, \infty)α∈(0,∞) and A=(12α101012)A = \begin{pmatrix} 1 & 2 & \alpha \\ 1 & 0 & 1 \\ 0 & 1 & 2 \end{pmatrix}A=110201α12. If det(adj(2A−AT)⋅adj(A−2AT))=28\det\bigl(\text{adj}(2A - A^T) \cdot \text{adj}(A - 2A^T)\bigr) = 2^8det(adj(2A−AT)⋅adj(A−2AT))=28, then (detA)2(\det A)^2(detA)2 is equal to:a.363636b.161616c.111d.494949Login to continueOnly logged in users canattempt or see the solution.
