1.Let a1,a2,…,a30a_1, a_2, \ldots, a_{30}a1,a2,…,a30 be an A.P., S=∑i=130aiS = \sum_{i=1}^{30} a_iS=∑i=130ai and T=∑i=115a2i−1T = \sum_{i=1}^{15} a_{2i-1}T=∑i=115a2i−1. If a5=27a_5 = 27a5=27 and S−2T=75S - 2T = 75S−2T=75, then a10a_{10}a10 is equal to:a.525252b.474747c.424242d.575757Login to continueOnly logged in users canattempt or see the solution.
