1.Let f:R−{3}→R−{1}f: \mathbb{R} - \{3\} \to \mathbb{R} - \{1\}f:R−{3}→R−{1} be defined by f(x)=x−2x−3f(x) = \frac{x-2}{x-3}f(x)=x−3x−2. Let g:R→Rg: \mathbb{R} \to \mathbb{R}g:R→R be given as g(x)=2x−3g(x) = 2x - 3g(x)=2x−3. Then, the sum of all the values of xxx for which f(x)+g(x)=2f(x) + g(x) = 2f(x)+g(x)=2 is equal toLogin to continueOnly logged in users canattempt or see the solution.