1.Let α,β\alpha, \betaα,β be two roots of the equation x2+201/4 x+(5)1/2=0x^2 + 20^{1/4}\,x + (5)^{1/2} = 0x2+201/4x+(5)1/2=0. Then α8+β8\alpha^8 + \beta^8α8+β8 is equal to:a.101010b.100100100c.505050d.160160160Login to continueOnly logged in users canattempt or see the solution.
