1.If tanθ+tan4θ+tan7θ=tanθtan4θtan7θ\tan \theta + \tan 4\theta + \tan 7\theta = \tan \theta \tan 4\theta \tan 7\thetatanθ+tan4θ+tan7θ=tanθtan4θtan7θ then the general solution isa.θ=nπ4\theta = \frac{n\pi}{4}θ=4nπb.θ=nπ12\theta = \frac{n\pi}{12}θ=12nπc.θ=nπ6\theta = \frac{n\pi}{6}θ=6nπd.None of theseLogin to continueOnly logged in users canattempt or see the solution.
