1.Let A=(12−2−5)A = \begin{pmatrix} 1 & 2 \\ -2 & -5 \end{pmatrix}A=(1−22−5). Let α,β∈R\alpha, \beta \in \mathbb{R}α,β∈R be such that αA2+βA=2I\alpha A^2 + \beta A = 2 IαA2+βA=2I. Then α+β\alpha + \betaα+β is equal to:a.−10-10−10b.−6-6−6c.666d.101010Login to continueOnly logged in users canattempt or see the solution.
