1.∫0π/2secxtanxsecx+tanx dx=\int_0^{\pi/2} \frac{\sec x\tan x}{\sec x+\tan x}\,dx =∫0π/2secx+tanxsecxtanxdx=a.π−2\pi-2π−2b.π+2\pi+2π+2c.π+22\frac{\pi+2}{2}2π+2d.π(π−2)2\frac{\pi(\pi-2)}{2}2π(π−2)Login to continueOnly logged in users canattempt or see the solution.