1.CH3COOH→LiAlH4A→H3O+A′+CH3COOH→30∘CB+H2O\text{CH}_3\text{COOH} \xrightarrow{\text{LiAlH}_4} \text{A} \xrightarrow{\text{H}_3\text{O}^+} \text{A}' + \text{CH}_3\text{COOH} \xrightarrow{30^\circ\text{C}} \text{B} + \text{H}_2\text{O}CH3COOHLiAlH4AH3O+A′+CH3COOH30∘CB+H2O. In the above reactions, A and B respectively are:a.CH3_33COOC2_22H5_55, C2_22H5_55OHb.CH3_33CHO, C2_22H5_55OHc.C2_22H5_55OH, CH3_33CHOd.C2_22H5_55OH, CH3_33COOC2_22H5_55Login to continueOnly logged in users canattempt or see the solution.
