1.If the position vectors of the vertices of △ABC\triangle ABC△ABC are OA→=3i^+j^+2k^\overrightarrow{OA} = 3\hat{i} + \hat{j} + 2\hat{k}OA=3i^+j^+2k^, OB→=i^+2j^+3k^\overrightarrow{OB} = \hat{i} + 2\hat{j} + 3\hat{k}OB=i^+2j^+3k^ and OC→=2i^+3j^+k^\overrightarrow{OC} = 2\hat{i} + 3\hat{j} + \hat{k}OC=2i^+3j^+k^, then the length of the altitude of △ABC\triangle ABC△ABC drawn from A isa.32\sqrt{\frac{3}{2}}23b.32\frac{3}{\sqrt{2}}23c.32\frac{\sqrt{3}}{2}23d.32\frac{3}{2}23Login to continueOnly logged in users canattempt or see the solution.