1.If fff and ggg are twice differentiable on (0,3)(0,3)(0,3) with f′′=g′′f''=g''f′′=g′′, f′(1)=4f'(1)=4f′(1)=4, g′(1)=6g'(1)=6g′(1)=6, f(2)=3f(2)=3f(2)=3, g(2)=9g(2)=9g(2)=9, then f(1)−g(1)=f(1)-g(1)=f(1)−g(1)=a.4b.-4c.0d.-2Login to continueOnly logged in users canattempt or see the solution.
