1.A solid non-conducting sphere has variable volume charge density ρ=ArR\rho = \dfrac{Ar}{R}ρ=RAr. If the electric field at distance R2\dfrac{R}{2}2R from the centre of the charged sphere is E=2Rε0 N/CE = \dfrac{2R}{\varepsilon_0}\,\text{N/C}E=ε02RN/C, the value of A16\dfrac{A}{16}16A will bea.222b.444c.666d.888Login to continueOnly logged in users canattempt or see the solution.