1.Let α∈(0,π/2)\alpha\in(0,\pi/2)α∈(0,π/2) be constant. If ∫tanx+tanαtanx−tanαdx=A(x)cos2α+B(x)sin2α+C\int \frac{\tan x+\tan\alpha}{\tan x-\tan\alpha}dx = A(x)\cos2\alpha + B(x)\sin2\alpha + C∫tanx−tanαtanx+tanαdx=A(x)cos2α+B(x)sin2α+C, then A(x),B(x)A(x), B(x)A(x),B(x) are respectivelya.x−αx-\alphax−α and loge∣sin(x−α)∣\log_e|\sin(x-\alpha)|loge∣sin(x−α)∣b.x+αx+\alphax+α and loge∣cos(x−α)∣\log_e|\cos(x-\alpha)|loge∣cos(x−α)∣c.x+αx+\alphax+α and loge∣sin(x+α)∣\log_e|\sin(x+\alpha)|loge∣sin(x+α)∣d.x−αx-\alphax−α and loge∣cos(x−α)∣\log_e|\cos(x-\alpha)|loge∣cos(x−α)∣Login to continueOnly logged in users canattempt or see the solution.
